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2 years ago

I WILL MARK BRAINLIEST J PLS ANSWER

Mathematics

1 answer:

trapecia [35]2 years ago

7 0

Answer:

small jets 213 large 632

Step-by-step explanation:

You might be interested in

I need help understanding how to solve this problem .

ladessa [460]

5*2x|x|-6=24

10*|x|-6=24

10*|x|=30

Divided both sides of the equation by 10

|x|=3

X=3 X=-3

4 0

2 years ago

What is the domain and range of this

Bond [772]

Domain: What are all the possible x values?
[-6, 0) U (0,2)

[ ] Closed brackets means including a number
( ) Open brackets means not including that number

Range: All possible y values
(1, 6]

6 0

2 years ago

a globe has a diameter of 24 inches. a smaller globe has a diameter of 18 inches. What is the surface are to volume ratio of the

faust18 [17]

Answer:

1 pi: 3pi

Step-by-step explanation:

Step 1: Formula of surface area and volume of sphere

Surface area of sphere = 4 x pi x r^2

Volume of sphere = 4 x pi x r^3

Step 2: Apply values in the formula

r = radius

radius = diameter/2

r=18/2 = 9

S.A = 4 x pi x 9^2

S.A = 324pi

Volume = 4 x pi x 9^3

Volume = 972pi

Step 3 : Show in ratio

Surface area : Volume

324pi : 972pi

= 1 pi: 3pi

6 0

3 years ago

Lawns by Brawns uses 13 ounces of fertilizer for 6.5 acres. Assume the company is fertilizing 0.5 of an acre. How much fertilize

notsponge [240]

13 for 6.5
X for 0.5
0.5/6.5*13=1
1 ounce for 0.5 arce

5 0

2 years ago

In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer

stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = percentage of patients stop smoking when given sustained care.

So, Null Hypothesis, $H_0$ : p = 80% {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, $H_A$ : p $\neq$ 80% {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of patients who stop smoking when given sustained care = 80.2%

n = sample of patients = 192

So, the test statistics = $\frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }$

= 0.07

The value of z test statistics is 0.07.

Also, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.07) = 1 - P(Z $\leq$ 0.07)

= 1 - 0.52790 = 0.4721

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0

3 years ago