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JulijaS [17]
2 years ago
5

Solve the following inequality. 2(P + 1) > 7 + P

Mathematics
1 answer:
olasank [31]2 years ago
8 0

Answer:

P > 5

Step-by-step explanation:

2(P + 1) > 7 + P

Distribute

2P +2 > 7+P

Subtract P from each side

2P -P +2 > 7+P -P

P +2 > 7

Subtract 2 from each side

P+2-2 > 7-2

P > 5

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You can think about the word ‘of’ when you multiply.
Vlada [557]

Answer:

23 \: of \: 6 \\ 23 \times 6 \\  =  >  \frac{ \binom{23}{ \times 6} }{138}  \\ 23 \: of \: 6 = 138

4 0
2 years ago
Read 2 more answers
You throw two four-sided dice. Let the random variable X represent the maximum value of the two dice. Compute E(X). Round your a
Troyanec [42]

Answer:

E(X)=3.125

Step-by-step explanation:

We are given that two four sided dice.

Then , the sample space

{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

Total number of outcomes=16

Let the random variable X represent the maximum value of the two dice

Outcomes                            X                                 P(X)

(1,1)                                          1                                 1/16

(1,2),(2,1),(2,2)                                   2                        3/16

(1,3),(2,3),(3,1),(3,2),(3,3)                    3                           5/16  

(1,4),(3,4) ,(2,4),(4,1),(4,2),(4,3),(4,4)    4                            7/16

Using the probability formula

P(E)=\frac{Favorable\;outcomes}{Total\;number\;of\;outcomes}

Now,

E(X)=\sum_{i=1}^{n}x_iP(x_i)

E(x)=1(1/16)+2(3/16)+3(5/16)+4(7/16)

E(x)=\frac{1+6+15+28}{16}

E(x)=\frac{50}{16}=3.125

7 0
3 years ago
The ball rolls downhill, its kinetic energy increases and its potential energy ________
lana [24]
Maximum. Hope you get it right!!
6 0
2 years ago
I will attach a screenshot of the math problem.
Alekssandra [29.7K]

Complete the table for the function y = 0.1^x

The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.

* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).

* 0.1^-1 = 1/0.1 = 10

* 0.1^0 = 1 : (Remember this rule: a^0 = 1)

* 0.1^1 = 0.1

Our list of values: 100, 10, 1, 0.1

Now, we can plug these values into your table:

\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]

The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]

I hope this helped!

7 0
2 years ago
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