For each child she spent $5 plus $15 = $20
120 divided by 20 = 6 subscriptions
It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :
X(X-1)(X-2)(X-3)(X-4)(X-5)(X+1)(X+2)(X+3)= X^9-9X^8+6X^7+126X^6-231X^5-441X^4+944X^3+324X^2-720X
This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5
And it has 3 negative zeros : - 1, -1, - 3
And it has 0 as a zero too.
There is also this one :
(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144
It has 4 positive zeros : 1, 2, 3, 4.
It has complex zeros : i and - i
3 negative zeros : - 1, - 2 , - 3
Good Luck
7: 2 -(4-7) + (-7) +10
2 +3 -7 +10
= 8
9: (-10) x (-5) + (-4) + 5 -(-10)
(50) -4 +5 +10
= 61
hope this helps :) (please mark brainliest!)
Answer:
A linear inequality graph usually uses a borderline to divide the coordinate plane into two regions. One part of the region consists of all solutions to inequality. The borderline is drawn with a dashed line representing '>' and '<' and a solid line representing '≥' and '≤'.
