<h2><u>Question</u>:-</h2>
Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters.
<h2><u>Answer</u>:-</h2>
<h3>Given:-</h3>
Radius (r) of a cylinder = 3 meters.
Height (h) of a cylinder = 13 meters.
<h3>To Find:-</h3>
The volume of a cylinder.
<h2>Solution:-</h2>
We know,
Formula of Volume of a cylinder is πr²h.
So, Volume of a cylinder = 3.14 × (3)² × 13
Volume of a cylinder = 3.14 × 3 × 3 × 13
Volume of a cylinder = 367.38 cubic meters.
<h3>The volume of a cylinder is <u>3</u><u>6</u><u>7</u><u>.</u><u>3</u><u>8</u><u> </u><u>cubic </u><u>meters</u>. [Answer]</h3>
Answer:
x <= - 4 2/3
Step-by-step explanation:
3(x-4) ≥ 6x+2
Distributive property
3x - 12 ≥ 6x+2
-12 ≥ 3x + 2
re-write
3x + 2 <= -12
3x <= -14
x <= -14/3
x <= - 4 2/3
Take it and divide it by 5, or you can multiply it by .2
Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ± 
* (S/√n)
6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!
