Question

Points y,B, and Q are shown on the coordinate plain. If Y,B and Q are the vertices of a triangle what is the perimeter to the nearest tenth of a unit of triangle YBQ

Answer 1

Answer: sqrt(61)

Step-by-step explanation:

For parts a) and c1), refer to the attached picture.

For part b), the distance formula is:

d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

Using x1 = -1, y1 = -4, x2 = -6, y2 = 2:

d = sqrt[(-6 + 1)^2 + (2 + 4)^2] = sqrt[25 + 36] = sqrt(61)

Part c2) Another way to find the length of AB without using the distance formula is by drawing the line and measuring it according to the scale.

Part d) This will only work as long as the graph paper is accurately made, and the scale computation is done correctly. However, this will only give approximations, and will not give an exact answer when radicals are involved.