1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nesterboy [21]
2 years ago
8

Brainliest to correct answer. Please help!!! Last year, Trevor gave $5,462 to his local charity, which he calculated as 22.5% of

his yearly salary. How much money does Trevor make in a year?
Mathematics
1 answer:
aniked [119]2 years ago
7 0

Answer:

6 690.95 US$

Step-by-step explanation:

You might be interested in
If 10% of x is 20, what is 23% of x?<br> A. <br> 33<br> B. <br> 46<br> C. <br> 200<br> D. <br> 230
dusya [7]

Answer:

46

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Jon borrows $6.50 from his friends to pay for snacks , and $11.75 from his sister to go to the movies. How much money does he ne
Naddik [55]

Answer:

$18.25

Step-by-step explanation:

5 0
2 years ago
14. A company uses many different delivery
ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that P(A) = 0.71

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that P(B|A) = 0.93

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0
2 years ago
The minimum wage in 2003 was $5.15. This was w more than the minimum wage in 1996. Write an expression for the minimum wage in 1
bekas [8.4K]
$5.15 - w = minimum wage in 1996

(if that wasn't what you were looking for then comment what you really wanted)
8 0
3 years ago
What is the midpoint of a line segment with endpoints (-2, 6) and (4, 3) in the
Inessa05 [86]

Answer:

(1, 9/2) or (1, 4.5)

Step-by-step explanation:

To find the midpoint, take the x1 and x2 values and divide it by 2, same for the y values.

(4-2)/2  and (6 + 3)/2

1 and 4.5

(1, 4.5)

3 0
3 years ago
Other questions:
  • How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy
    7·1 answer
  • Explanation A random sample of 100 observations from a normally distributed population possesses a mean equal to 83.2 and a stan
    13·1 answer
  • Determine the intercepts of the line.
    10·2 answers
  • Set 4x equal to x+30 and solve.
    14·1 answer
  • <img src="https://tex.z-dn.net/?f=%20x%20-%202%5Csqrt%7Bx%20-%203%20%3D%200%7D%20" id="TexFormula1" title=" x - 2\sqrt{x - 3 = 0
    14·1 answer
  • There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?
    11·2 answers
  • The directions for a jewelry-making pattern call for a chain 358 inches long. When shopping for a chain, the following choices w
    10·2 answers
  • Amanda works as a hostess at Red Robin on weekday nights and at the Pix movie theatre on the weekends. Amanda’s pay at Red Robin
    7·1 answer
  • -2(-5 - 2) + (2)/(3)
    15·1 answer
  • Help!!Find the y-intercept of the line on the graph.<br> Enter the correct answer.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!