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scoray [572]
3 years ago
7

tim has been offered three jobs. job a paid on an annual basis with a salary of 26,700. job b pays $500 per week. job c pays &am

p;1,125 semimonthly. which job pays the most per year?
Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

Job C

Step-by-step explanation:

Since he's paid semi monthly,literally half a month, which is 1125$

Then full month will be 1125×2

Which is 2250

Then annually would be 2250×12=27,000

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In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

                                                                     and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

\frac{x}{z}= \frac{p}{x}

Cross multiply

x^{2}=pz

Hence proved.


7 0
3 years ago
What value of x is in the solution set of 9(2x + 1) &lt; 9x - 18? -4 -3 -2 -1​
Zanzabum

Answer:

what does -4,-3,-2,-1 implies?

6 0
3 years ago
Read 2 more answers
PQRS is a parallelogram. Find the m
viktelen [127]

Answer:

Step-by-step explanation:

<R=<P=70degrees

<Q=180-70=110 degrees

7 0
3 years ago
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PLS HELP COME QUICK!!!!!!!
Andrews [41]
Minus 36 from each one you can do it on a calculator:)
8 0
3 years ago
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
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