1) p + 8
Substitute 2 in for the variable.
2 + 8 =

2) 3p
Substitute 2 in for the variable.
3(2) =

3) 16 - p
Substitute 2 in for the variable.
16 - 2 =

4) -12 ÷ p
Substitute 2 in for the variable.
-12 ÷ 2 =
Answer:
Step-by-step explanation:
a) Denote the event of commercially availability of f_uel cell technology as F_, commercial availability of solar power technology as S
Write the probability of energy supplied by these energy sources in the next 10 years
P(energy supplied) = P(S ∪ F) -----(1)
Rewrite eqn (1)
P(energy supplied) = P(S) + P(F) - P(F) P(S) ----(2)
substitute 0.85 for P(S) and 0,7 for P(F) in eqn (2) to find the probability of energy supplied by these energy sources
P(energy supplied) = 0.85 + 0.7 - (0.7 * 0.85)
= 0.85 + 0.7 - (0.595)
= 1.55 - 0.595
= 0.955
Therefore, the probability that there will be energy supplied by these two alternative sources in the next 10 years is 0.955
B) write the probability of only one source of energy available
P(only one source of energy available) =
∪
---(3)
Rewrite the equation (3)
P(only one source of energy available) =
![=P(\bar F S)+P(\bar S F)\\\\=\{[1-P(F)]P(S)+[1-P(S)]P(F)\}---(4)](https://tex.z-dn.net/?f=%3DP%28%5Cbar%20F%20S%29%2BP%28%5Cbar%20S%20F%29%5C%5C%5C%5C%3D%5C%7B%5B1-P%28F%29%5DP%28S%29%2B%5B1-P%28S%29%5DP%28F%29%5C%7D---%284%29)
![=\{[1-0.7]0.85+[1-0.85]0.7\}\\\\=0.255+0.105\\\\=0.36](https://tex.z-dn.net/?f=%3D%5C%7B%5B1-0.7%5D0.85%2B%5B1-0.85%5D0.7%5C%7D%5C%5C%5C%5C%3D0.255%2B0.105%5C%5C%5C%5C%3D0.36)
Therefore,The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years is 0.36
Answer:
D. 29% and 22%
Step-by-step explanation:
The known percentages are 34% and 15%. Add these two together to get 49%. All four choices should add up to 100%. So subtract to find what remains:
100% - 49%
= 51%
We don't actually have enough information to determine the percents for summer and winter. BUT the only answer that adds up to 51% is answer D. 29% and 22%.