Answer:
SA = 2πr² + 2πrh
Step-by-step explanation:
2πr² will provide the surface area of the top and bottom of the cylinder
2πrh will provide the surface area of the cylinder portion that connects the top and bottom
<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore , this can be written as ,
![\implies \sqrt[4]{13^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B4%5D%7B13%5E3%7D%20)
<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>
Given expression ,
We know that,
Therefore, this can be written as ,

Answer:
A. 1/8
Step-by-step explanation:
m = rise/run
m = (y2-y1)/(x2-x1)
m = (-5- - 4)/(1-9)
m = (-5+4)/(-8)
m = (-1)/(-8)
m = 1/8
Answer:
D. x = 5.4, y = 6.67
Step-by-step explanation:
The triangles are similar as per problem description, so the ratios match:
y/5 = 4/3
x/3 = 9/5
let's solve:
y/5 = 4/3
3y/5 = 4
3y = 20
y = 6.(6)
x/3 = 9/5
5x/3 = 9
5x = 27
x = 5.4