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Leokris [45]
3 years ago
5

Which expression has a solution of 54, if t=6?

Mathematics
2 answers:
Ksivusya [100]3 years ago
7 0

Answer

tx=54

6x =54

x=9

Anuta_ua [19.1K]3 years ago
6 0
The answer is 9t because 9 times 6 is = 54
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Which point of concurrency is the center of gravity in a triangle
ipn [44]
Answer: centroid
Reasoning: The centroid is the point of concurrency of the three medians in a triangle.
3 0
3 years ago
3x+4(x-8)-14 evaluate for x=11
djverab [1.8K]

Answer:

For X = 11, the expression is equal to 31

Step-by-step explanation:

Hello

For X = 11 you only have to replaced the value into the expression, so:

3(11) + 4(11-8) - 14

33 + 4(3) - 14

33 + 12 - 14

31

Best regards

4 0
3 years ago
Read 2 more answers
A city has a population of 230,000 people. Suppose that each year the population grows by 8.5%. What will the population be afte
worty [1.4K]

Answer:

720,682.92

Step-by-step explanation:

8.5% = 0.085

P(t) = Initial Population * (1 + rate)t

P(t) = 230,000(1 + 0.085)t

P(t) = 230,000(1.085)t

P(14) = 230,000(1.085)14

P(14) = 720,682.82

6 0
3 years ago
If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?
irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV

Read more about quadrants at:

brainly.com/question/7196312

#SPJ1

6 0
2 years ago
-25 Points-
Over [174]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{8}}{\sqrt[3]{125}}\implies \cfrac{s}{s}=\cfrac{2}{5}\qquad \leftarrow \textit{ratio of the sides or scale factor}

8 0
3 years ago
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