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Nata [24]
3 years ago
13

Si Mark ay nakagawa ng 84 na pirasong cookies. Kung ang mga ito ay kaniyang isisilid sa 7 maliliit na kahon. Ilang

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0
1. Nakagawa siya ng 84 na cookies.
2. Inilagay niya ang mga cookies sa 7 na kahon.
3. 84 ÷ 7 = 12
4. 12 x 7 = 84
5. Ang bawat lalagyan ay may 12 na cookies sa loob nito.
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Anyone help with this?
Mrac [35]

Answer:

3 degrees

Step-by-step explanation:

They are the same because they are on opposite sides of each other. If u look at the picture, angle a and b are the same size.

4 0
2 years ago
Please help!
Marat540 [252]

Answer: width = 82.50 m

Step-by-step explanation:

P = 2l x 2w

425 = 2(130) + 2w

425 - 260 = 2w

w = 165 / 2 = 82.50

5 0
3 years ago
Pink rose plants are on sale for $3 each and white ones for $5 each. A gardener decides to buy 13 in total, choosing more white
Anettt [7]

Answer:

8

Step-by-step explanation:

If the gardener bought more white than pink, that could mean he could have bought 12 white and one pink, 11 white and 2 pink, 10 white and 3 pink, 9 white and 4 pink, 8 white and 5 pink, or 7 white and 6 pink.

If you plug in the numbers, for example with 7 and 6, that would equal $53, which is not correct. Continue to do this with all of the answers.

With 8 white roses and 5 pink roses, this would equal $55 (40+15), which is the answer.

7 0
2 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
PLEASE HELPPPP!! The options are <br> DC= AB<br> AC=AC
Rom4ik [11]

Answer:

the 1st one

Step-by-step explanation:

because A<C are the only angle ur missing.

3 0
3 years ago
Read 2 more answers
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