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2 years ago

8

What is the Length of side ML ?

1 answer:

elena-14-01-66 [18.8K]2 years ago

6 0

9 is correct answer because it is given that ML=LB.

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Lola plans to publish a magazine. She cannot publish unless she sells at least 100 subscriptions. Each subscription costs $20. T

dedylja [7]

Answer:

R(s) $\geq 2000$ ,

Step-by-step explanation:

The function R(s) = 20s

She needs to sell at least 100 subscriptions, so the least amount she wants to have is: 20*100 = $2000

Hence, is the domain of R(s) in this context

R(s) $\geq 2000$

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3 years ago

The length of the ears on the shadow puppet is 3 inches. The length of the ears on the shadow is 4 inches. What is the scale fac

Rufina [12.5K]

The scale factor is the number u multiply by the first image to get to the second image.

so 3 times what = 4
3x = 4
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2 years ago

(7 x 10^5) ÷(2 x 10²)

12345 [234]

Answer:

<h2> $3.5 * 10x^{3}$ </h2>

Expanded Form:

3500

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

Sarah goes to a bakery to buy doughnuts for work.

frosja888 [35]

Answer:

The equation i came up with is $55= 7.8x - 47.20

5 0

2 years ago

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago