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9966 [12]
2 years ago
14

Solve for x in the rectangle below​

Mathematics
2 answers:
timurjin [86]2 years ago
7 0

Answer:

Where is the rectangle?

Step-by-step explanation:

Alik [6]2 years ago
6 0

Answer:

There isnt a rectangle buddy

Step-by-step explanation:

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What is the circumference of the circle use 22 over 7 for pi​
melamori03 [73]
Pi= 3.14159265358979323
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2 years ago
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What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is 
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}

Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70} 
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median. 

The value in the 8th slot is 54, so this is the median

Divide the sorted data set into two lists. I'll call them L and U 
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).

Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value. 

Therefore, Q3 = 62

Answer: 62</span>
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3 years ago
Questions in-the attachments if yk pls help I’ll give brainlist
vovangra [49]
The answer is A

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2 years ago
Find the equation of a parabola with a focus at (0,-1) and a directrix at y = 4.
Anastasy [175]

Answer:

  y = -1/10x^2 +2.5

Step-by-step explanation:

The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:

  -1 -4 = -5

So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).

The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...

  y = (1/(4p))(x -h) +k

  y = -1/10x^2 +2.5

_____

You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.

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3 years ago
Math question down below
Bas_tet [7]
I would say 25 is the answer to it
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