Given:
The graph of linear function.
To find:
The slope intercept form of the linear equation from the given graph.
Solution:
The slope intercept form of a linear function is:
From the given graph it is clear that the graph passes through the points (1,300) and (4,800).
The equation of line is
Adding 300 on both sides, we get
Therefore, the required equation is .
The slope of the line shown in the figure having equation x + 2y = 0 is 1/2.
The point A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and Point C is at ( -2 , 2 ).
Let point D be at ( -4 , 1 ).
Now the new triangle is ΔBDA and the corner points are A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and point D is at ( -4 , 1 ).
The equation of line passing through two points is given by:
The equation of line passing through two points A( -2 , 1 ) and B( -4 , 2 ) IS
y - 1 = ((2-1)/(-4-(-2))) (x-(-2))
y - 1 = (1/(-2)) (x+2)
2y -2 = -x -2
x + 2y = 0
The equation of straight line is x + 2y = 0
The equation in slope intercept form can be written as,
y = x/2 + 0
Slope = m = 1/2
Intercept = c = 0
So, we can conclude that 1/2 is the slope of the line .
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