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3 years ago

The equation X^3+3x^2 + 5x+15 = 0 Has how many solutions

1 answer:

8 0

x
=
-
3
,
5
,
-
5
The result can be shown in multiple forms.
Exact Form:
x
=
−
3
,
√
5
,
−
√
5
x
=
-
3
,
5
,
-
5
Decimal Form:
x
=
−
3
,
2.23606797
…
,
−
2.23606797
…

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A number is chosen at random from 1 to 50. Find the probability of selecting either a multiple of 4 or a multiple of 5.

anygoal [31]

A multiple of 4 is a 12/50 chance and a multiple of 5 is a 10/50 chance or simplified 1/5 chance

6 0

3 years ago

Read 2 more answers

Write a problem that uses a fraction greater than 1.

Gennadij [26K]

3/2+3/2=3 That is a good equation because all of the characters are bigger than one 3/2 is equal to 1.5 and 3 is greater than 1

5 0

3 years ago

Read 2 more answers

Can someone please help me its urgent!!!!!!!!!!<br> 3x + 11 = 3x - 11

user100 [1]

Answer:

$\Large\boxed{\mathsf{\Rightarrow NO\quad SOLUTIONS}}$

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

Isolate by the x on one side of the equation.

<h3><u>SOLUTIONS:</u></h3>

First, subtract 3x from both sides.

$\displaystyle \Rightarrow \mathsf{3x+11-3x=3x-11-3x}}$

Solve.

$\displaystyle \mathsf{11=-11}$

Sides are NOT equal.

$\Large\boxed{\mathsf{\Rightarrow THERE \quad ARE \quad NO \quad SOLUTIONS}}}$

Therefore, there are no solutions.

6 0

3 years ago

Pls help asap, find the height of the cylinder and round to the nearest tenth

Elena L [17]

Answer:

h = 2.4

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

271.4 = pi ( 6)^2 *h

271.4 = 36* pi* h

Letting 3.14 = pi

271.4 = 113.04 h

Divide each side by 113.04

271.4 /113.04 = 113.04h/113.04

2.424805379 = h

Rounding to the nearest tenth

2.4 = h

OR if we use the pi button

271.4 = 36 * pi *h

Divide each side by 36 pi

271.4/36pi = h

h=2.3997

Rounding to the nearest tenth

h =2.4

3 0

2 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago