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svetoff [14.1K]
3 years ago
9

Plz I need help with only the perimeter one

Mathematics
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

25.4

Step-by-step explanation:

add em up then put the .3 after you add it up

Tcecarenko [31]3 years ago
5 0

Answer:

I believe the answer is 25.3

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Firlakuza [10]

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6/16=0,375

0,375*30=11,25

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5. Higher Order Thinking Maria has two
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10$ bill

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2 20$ is 40 + 5(3) = 55+4 = 59$ then 69-59=10$

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Which point is 12 units less than point Q?
nadezda [96]

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Point R

Step-by-step explanation:

Go back 12 points

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3 years ago
Residences of U.S. Citizens According to the U.S. Census, 67.5% of the U.S. population were born in their state of residence. In
trasher [3.6K]

Answer:

P(X < 126) = 0.0418

Step-by-step explanation:

To solve this question, we use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Sample of 203, 67.5% of the U.S. population were born in their state of residence.

This means that n = 203, p = 0.675

So, for the approximation:

\mu = E(X) = np = 203*0.675 = 137.025

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{203*0.675*0.325} = 6.67

What is the probability that fewer than 126 were born in their state of residence?

Using continuity correction, this is P(X < 126 - 0.5) = P(X < 125.5), which is the pvalue of Z when X = 125.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{125.5 - 137.025}{6.67}

Z = -1.73

Z = -1.73 has a pvalue of 0.0418

So

P(X < 126) = 0.0418

8 0
3 years ago
A high school booster club is selling raffle tickets for three different prizes. The tickets are $1 for the small prize, $2 for
Ivan

Answer:

x+y+z=15

x+2y+5z=15

-x+y+z=1

Step-by-step explanation:

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