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Ludmilka [50]
3 years ago
11

Can someone help plz

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

84g

Step-by-step explanation:

399÷19=21

21 x 4 = 84

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PLEASE HELP
lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
1 year ago
Find the area of the rectangle with measurements shown; reduce to lowest terms:
AleksandrR [38]

Answer:

4/5

Step-by-step explanation:

the area of rectangle is length × breadth

length = 2 2/5 breadth = 1/3

2 2/5 × 1/3 = 12/15

reducing to the lowest term =4/5

Step-by-step explanation:

8 0
3 years ago
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It Takes 40 minutes for 8 people to paint 4 walls
Nana76 [90]

Answer: 70

Step-by-step explanation:

10 x 7


5 0
3 years ago
You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides
Bess [88]
This problem can be solved by manipulating the formula for power, which is: P = VI. Where:

P = Power in watts
V= Voltage in volts
I = Current in amperes

Since we are already given the power and voltage, simple substitution can be done.

P = VI
3.5 watts = 120 volts * I
I = 3.5 / 120
I = 0.0292 Amperes or 29.2 milliAmperes

Therefore, the current through the bulb is 29.2mA
5 0
3 years ago
....................answer
Oksana_A [137]

Answer:

d. 2

Step-by-step explanation:

8 0
3 years ago
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