Answer:
x² + 2ax + a² + 5x + 5a + 4
Step-by-step explanation:
Formula -
( a + b )² = a² + 2ab + b²
Steps -
( x + a )² + 5 ( x + a ) + 4
x² +2ax + a² + 5 ( x + a ) + 4
x² + 2ax + a² + 5x + 5a + 4
Answer: 
Step-by-step explanation:
Given
Mark up price is 25% higher than cost price
The shopkeeper gives a discount of 10%
Suppose the cost price is 
Mark up price is 
Selling price is
It is given Rs150
Marked up price is 
Not sure i remember this but i think radius is like half of the diameter. it’s a line from the center, to a side of the circle. in this situation, line RO would be representing the radius.
answer: D, line RO
hope this helps :)
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
C.21
5^2-4=21
Explanation
