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3 years ago

What does the equation y=2x + 3 represent relationship.

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

6 0

Answer:

Linear Proportional Relationship

General Formulas and Concepts:

Algebra I

Linear - Any degree of 1 in the form of y = mx + b or Ax + By = C
Nonlinear - Any degree higher than 1

Step-by-step explanation:

Step 1: Define

y = 2x + 3

Step 2: Identify

We see we have a linear equation in y = mx + b. We can also see that it is a degree of 1. Therefore, it is a Linear proportional relationship.

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Solve the systems by the addition method 2x + y = - 1x - 2y = - 4

inna [77]

Answer:

x = -6/5

y =7/5

Step-by-step explanation:

2x + y = - 1

x - 2y = - 4

Multiply the first equation by 2 so we can eliminate y

2(2x + y = - 1)

4x + 2y = -2

Add this to the second equation

4x + 2y = -2

x - 2y = - 4

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5x + 0y = -6

Divide by 5

5x/5 = -6/5

x = -6/5

Multiply the second equation by -2 so we can eliminate x

-2(x - 2y = - 4)

-2x+4y = 8

Add this to the first equation

2x + y = - 1

-2x+4y = 8

---------------------

0x + 5y = 7

Divide by 5

5y/5 = 7/5

y =7/5

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3 years ago

A rectangle has dimensions of 12 cm long and 10 cm wide what is the area of the rectangle

LiRa [457]

The area and the width are known as 60 and 12 respectively. Rearranging that equation above, and plugging the values, one gets the value of the length of the rectangle as 5.

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3 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

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4 years ago

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Answer:

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Step-by-step explanation:

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