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3 years ago

What does the equation y=2x + 3 represent relationship.

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

6 0

Answer:

Linear Proportional Relationship

General Formulas and Concepts:

Algebra I

Linear - Any degree of 1 in the form of y = mx + b or Ax + By = C
Nonlinear - Any degree higher than 1

Step-by-step explanation:

Step 1: Define

y = 2x + 3

Step 2: Identify

We see we have a linear equation in y = mx + b. We can also see that it is a degree of 1. Therefore, it is a Linear proportional relationship.

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Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3

LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128} = 8 \sqrt{2}$

Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

Questions 4 and 5 are not clear

Follow the steps in 1 - 3 to solve 4 and 5

7 0

3 years ago

What is the exponential expression for the numerical expression 14⋅14⋅14⋅14?

SVEN [57.7K]

It may be 1^4 ............................

7 0

3 years ago

Calculate the value of A in the statement

tigry1 [53]

please edit your question man

4 0

3 years ago

An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.

faltersainse [42]

Answer:

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

$y=a(x-h)^2+k$ , (h,k) is the center

$y=a(x-50)^2+25$

the parabola starts at (0,0) that is (x,y)

$0=a(0-50)^2+25$

subtract 25 from both sides

$-25=a(-50)^2$

$-25=a(2500)$

divide both sides by 2500

$a=-\frac{1}{100}$

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

$y=-\frac{1}{100}(40-50)^2+25$

y=24

the height of the arch 10 feet from the center is 24 feet

4 0

3 years ago

What are two numbers that add up to 70 without regrouping?

dedylja [7]

Any of the tens i think (10=60, 20+50, etc.), but i am not too sure what is implied by regrouping. if i am right in thinking this only means "carrying" a digit after adding, then anything that adds up to 70 would work unless the sum of the digits in the ones place exceeded 9.

6 0

3 years ago