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makvit [3.9K]
3 years ago
13

Opening Exercise

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

Jayla: 100th number is 200

Yaseen: 100th number is 8

Elijah: 100th number is 0

You might be interested in
Max and Sasha exercise a total of 20 hours each week. Max exercises 15 hours less than 4 times the
navik [9.2K]

Answer:

Max exercises 13 hours a week, and Sasha 7.

Step-by-step explanation:

To find the number of hours each of them exercises during the week, we solve the system of equations.

In the second equation:

x = 4y - 15

Replacing in the first equation:

x + y = 20

4y - 15 + y = 20

5y = 35

y = \frac{35}{5}

y = 7

So Sasha exercises 7 hours per week.

Max:

x + y = 20

x + 7 = 20

x = 13

Max exercises 13 hours a week.

6 0
3 years ago
Situation A
Colt1911 [192]

The equation a = 100 + 75d represents Maria's  account balance.

<u>Step-by-step explanation:</u>

Given that,

  • Maria opened a new savings  account with an initial deposit of  $100.
  • She deposits $75 into this  savings account every  two-weeks.

You need to find the equation to represent Maria's  account balance, a after she has  completed d deposits.

  • Let 'd' be the number of deposits Maria made after the initial deposit.
  • Let 'a' be the total account balance after 'd' deposits.

Therefore, the equation for the total account balance can be framed as the sum of the initial deposit and amount deposited after that.

<u>To find the amount that was deposited after the initial deposit :</u>

⇒ $75 × number of times Maria deposited.

⇒ 75 × d

The equation is written as,

⇒ a = 100 + 75d

Hence the equation a = 100 + 75d represents Maria's  account balance.

7 0
3 years ago
A model satellite has a scale of 1 in: 6 ft.
insens350 [35]

Answer:

B) 18 ft

Step-by-step explanation:

The scale is 1 in. model : 6 ft real.

6/1 = 6

To go from model size to real size, multiply the model size by 6 and change from inches to feet.

3 in. model = 3 × 6 ft = 18 ft

5 0
1 year ago
Find the volume of this sphere please <br><br> As soon as possible.
seropon [69]
<h3>Answer:   30</h3>

==========================================================

Explanation:

"Use 3 for pi" is something I've never seen a teacher do before. Usually it's "use 3.14 for pi".

Anyway, the diameter of this cylinder is 2 inches, which cuts in half to 1 inch. This is the radius.

The height is 10 inches.

So we have r = 1 and h = 10

V = pi*r^2*h

V = 3*1^2*10

V = 30 cubic inches approximately

3 0
3 years ago
Read 2 more answers
The diagram shows a regular octagon ABCDEFGH. Each side of the octagon has length 10cm. Find the area of the shaded region ACDEH
Zolol [24]

The area of the shaded region /ACDEH/ is 325.64cm²

Step 1 - Collect all the facts

First, let's examine all that we know.

  1. We know that the octagon is regular which means all sides are equal.
  2. since all sides are equal, then all sides are equal 10cm.
  3. if all sides are equal then all angles within it are equal.
  4. since the total angle in an octagon is 1080°, the sum of each angle within the octagon is 135°.

Please note that the shaded region comprises a rectangle /ADEH/ and a scalene triangle /ACD/.

So to get the area of the entire region, we have to solve for the area of the Scalene Triangle /ACD/ and add that to the area of the rectangle /ADEH/

Step 2 - Solving for /ACD/

The formula for the area of a Scalene Triangle is given as:

A = \sqrt{S(S-a)(S-b)(S-c) square units}

This formula assumes that we have all the sides. But we don't yet.

However, we know the side /CD/ is 10cm. Recall that side /CD/ is one of the sides of the octagon ABCDEFGH.

This is not enough. To get sides /AC/ and /AD/ of Δ ACD, we have to turn to another triangle - Triangle ABC. Fortunately, ΔABC is an Isosceles triangle.

Step 3 - Solving for side AC.

Since all the angles in the octagon are equal, ∠ABC = 135°.

Recall that the total angle in a triangle is 180°. Since Δ ABC is an Isosceles triangle, sides /AB/ and /BC/ are equal.  

Recall that the Base angles of an isosceles triangle is always equal. That is ∠BCA and ∠BAC are equal. To get that we say:

180° - 135° = 45° [This is the sum total of ∠BCA and ∠BAC. Each angle therefore equals

45°/2 = 22.5°

Now that we know all the angles of Δ ABC and two sides /AB/ and /BC/, let's try to solve for /AC/ which is one of the sides of Δ ACD.

According to the Sine rule,

\frac{Sin 135}{/AC/} = \frac{Sin 22.5}{/AB/} = \frac{Sin 22.5}{/BC/}

Since we know side /BC/, let's go with the first two parts of the equation.

That gives us \frac{0.7071}{/AC/}  = \frac{0.3827}{10}

Cross multiplying the above, we get

/AC/ = \frac{7.0711}{0.3827}

Side /AC/ = 18.48cm.

Returning to our Scalene Triangle, we now have /AC/ and /CD/.

To get /AD/ we can also use the Sine rule since we can now derive the angles in Δ ABC.

From the Octagon the total angle inside /HAB/ is 135°. We know that ∠HAB comprises  ∠CAB which is 22.5°, ∠HAD which is 90°. Therefore, ∠DAC = 135° - (22.5+90)

∠DAC = 22.5°

Using the same deductive principle, we can obtain all the other angles within Δ ACD, with ∠CDA = 45° and ∠112.5°.

Now that we have two sides of ΔACD and all its angles, let's solve for side /AD/ using the Sine rule.

\frac{Sin 112.5}{/AD/} = \frac{Sin 45}{18.48}

Cross multiplying we have:

/AD/ = \frac{17.0733}{0.7071}

Therefore, /AD/ = 24.15cm.

Step 4 - Solving for Area of ΔACD

Now that we have all the sides of ΔACD, let's solve for its area.

Recall that the area of a Scalene Triangle using Heron's formula is given as

A = \sqrt{S(S-a)(S-b)(S-c) square units}

Where S is the semi-perimeter given as

S= (/AC/ + /CD/ + /DA/)/2

We are using this formula because we don't have the height for ΔACD but we have all the sides.

Step 5 - Solving for Semi Perimeter

S = (18.48 + 10 + 24.15)/2

S = 26.32

Therefore, Area =  \sqrt{26.32(26.32-18.48)(26.32-10)(26.32-24.15)}

A = \sqrt{26.32 * 7.84*16.32 * 2.17)}

A = \sqrt{7,307.72} Square cm.

A of ΔACD = 85.49cm²

Recall that the shape consists of the rectangle /ADEH/.

The A of a rectangle is L x B

A of /ADEH/ = 240.15cm²


Step 6 - Solving for total Area of the shaded region of the Octagon

The total area of the Shaded region /ACDEH/, therefore, is 240.15 + 85.49

= 325.64cm²


See the link below for more about Octagons:
brainly.com/question/4515567

8 0
3 years ago
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