The solution to the system of equation are x = -2 and y = 3
<h3>How to find the solution of a system of equation?</h3>
x + 3y = 7
2x + 4y = 8
Let's isolate x in the first equation
x = 7 - 3y
substitute the value of x in the second equation.
Therefore,
2(7 - 3y) + 4y = 8
14 - 6y + 4y = 8
-2y = 8 - 14
-2y = -6
y = -6 / -2
y = 3
Hence,
x + 3(3) = 7
x = 7 - 9
x = -2
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For a system of equations to have infinitely many solutions it must describe identical lines.
If you multiply the first equation by 2, then move the x term to the left side, you would get 2y-4x=-10
Final Answer:
-10
Hope I helped :)
Answer:
-0.4 = −2/5
Step-by-step explanation:
Rewrite the decimal number as a fraction.
-0.4/1
Multiply to remove 1 decimal places.
-0.4/1 x 10/10 =4/10
Find the GCF.
4 ÷ 2/10 ÷ 2 = 2/5
x = 2/5
-2/5
For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
78
Step-by-step explanation:
