Answer:
Y = -X - 7
Step-by-step explanation:
y-y1 =m(x-x1)
y-(-2)= -1(x-(-5)
y+2 = -1(x+5)
Solve for y
subtract 2 from both sides
y=-x-5-2
Y = -x-7
100m= 0.621371 miles
11 seconds = 0.0030556 hours
s=d/t
0.0621371miles/0.0030556hours = 20.3355miles/hours
round off to 20.3 miles per hour
Speed = distance/time
distance = speed * time
let x = time covered by running
15 = run distance + walk distance
15 = 9(x) + 3(3-x)
15 = 9x + 9 - 3x
15 - 9 = 6x
6 = 6x
x = 1 hour
Therefore:
Running distance = speed * time
RD = 9km/hr * 1 hr
RD = 9km
<u>Note: The only way to solve this problem is by adjusting the fees to $3.50 and $7.50.</u>
Answer:
<em>1300 children attended the basketball game</em>
Step-by-step explanation:
System of Equations
Let's call:
x = number of children attending the basketball game
y = number of adults attending the basketball game
On a certain night, 1500 people enter the game, thus:
x + y = 1500 [1]
Since each admission fee for children cost $3.50 and $7.50 for adults and it was collected $6050, thus:
3.50x + 7.50y = 6050 [2]
From [1]:
y = 1500 - x
Substituting in [2]:
3.50x + 7.50(1500 - x) = 6050
Operating:
3.50x + 11250 - 7.50 = 6050
-4x = 6050 - 11250
Solving:
x = 1300
1300 children attended the basketball game
Perimeter (p) = 2×length (l) + 2×width (w)
p = 2l+2w
area (a) = l×w, so solve for one (I'll use l):
since p = 30, and a = 50, substitute the "a÷w" in for l in the perimeter equation:
Now plug in p and a values:
therefore width can be either 5 or 10 (but not both), so let's plug in:
l = a÷w = 50÷5 = 10
So if w = 5, then l = 10
D) 5 feet, and 10 feet
