Question

A bowl of fruit is on the table. It contains 5 apples, 2 oranges, and 2 bananas. Christian and Aaron come home from school and randomly grab one fruit each. What is the probability that both grab oranges?

Answer 1

The probability that both grab oranges would be = $\frac{1}{36}$

Step-by-step explanation:

Given,

A bowl contains,

Apples = a = 5

Oranges = o = 2

bananas = b = 2

Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9

Now, Christian and Aaron come home from school and randomly grab one fruit each.

The probability of first selecting orange would be = $\frac{o}{b} = \frac{2}{9}$

Now, the oranges left would be 2 - 1 = 1

and total fruits would be = 9 - 1 = 8

Hence, the probability of selecting second orange would be = $\frac{1}{8}$

Therefore, the probability that both grab oranges would be = $\frac{1}{8} * \frac{2}{9} = \frac{1}{36}$