A bowl of fruit is on the table. It contains 5 apples, 2 oranges, and 2 bananas. Christian and Aaron come home from school and r
1 answer:
The probability that both grab oranges would be =
Step-by-step explanation:
Given,
A bowl contains,
Apples = a = 5
Oranges = o = 2
bananas = b = 2
Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9
Now, Christian and Aaron come home from school and randomly grab one fruit each.
The probability of first selecting orange would be =
Now, the oranges left would be 2 - 1 = 1
and total fruits would be = 9 - 1 = 8
Hence, the probability of selecting second orange would be =
Therefore, the probability that both grab oranges would be =
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Step-by-step explanation:
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Answer:
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
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