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3 years ago

14

kelvin and 4 of his friends want to share 4 pounds of nuts equally. write an expression to show what fraction of nuts each frien

d should receive.

1 answer:

dimulka [17.4K]3 years ago

7 0

Each friend should get 20% of 4 pounds
kelvin should get 20% as well.
everyone gets: 0.8 pounds of nuts.

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Evaluate 15+w for w=6

svetlana [45]

Answer:

21

Step-by-step explanation:

To evaluate, substitute w = 6 into the expression, that is

15 + w = 15 + 6 = 21

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3 years ago

PLEASE HELP ANSWER THIS ASAP!!! :)

PilotLPTM [1.2K]

Answer:

C, 42 degrees

Step-by-step explanation:

Considering angle BAD is 60 degrees, that makes angle BCD also 60 degrees. Since parallelograms have 360 degrees in total, we're still missing 240 degrees. Since angles BAD and BCD are congruent (equal), that means that angles ABC and ADC also have to be congruent. To find their angles, we do 240 divided by 2, which equals 120. Now that we know all of the angles, lets focus on angle ADC. Since angle 1 has been given to us, all we need to do is subtract 78 from 120 which turns out to be 42 degrees, which is the answer.

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3 years ago

C/9 - 8 = 17<br> Solve the equation and show all work please show steps!!

Amiraneli [1.4K]

<span>C/9 - 8 = 17
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Simplify
1/9c - 8 = 17
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Add 8 to each side
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3 years ago

What is the probability of living another year for a woman who is 73 years old ?

AlladinOne [14]

Answer:

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Step-by-step explanation:

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Hence, the probability of living another year is :

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3 years ago

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

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$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

4 years ago