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podryga [215]
3 years ago
5

Evaluate the following expression. 153^0

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0
The answer would be 1. Anything to the power of 0 is one.
laiz [17]3 years ago
3 0
Any number except 0 to the power of 0 is 1.
Thus,
153⁰ = 1
You might be interested in
A right triangular prism and its net are shown below.
Law Incorporation [45]

Answer:

A=2

B=12

C=5

D=13

SA=411mm

Step-by-step explanation:

SA=bh+(s1+s2+s3)H

=12×5+(12+2+13)(13)

6 0
2 years ago
Read 2 more answers
#2
I am Lyosha [343]

You have the right idea that things need to get multiplied.

What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.

Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.

The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.

So we multiply the entire complex fraction by (5)(x + 6)(x -3).

Numerator: (\frac{1}{5} -\frac{5}{x + 6})(5)(x +6)(x-3) =\frac{1}{5}(5)(x +6)(x-3) -   \frac{5}{x + 6}(5)(x +6)(x-3)

= (x+6)(x-3) - (5)(5)(x-3)

= (x+6)(x-3) - 25(x-3)

= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3

= (x -3)(x - 19)

Denominator:

\frac{25}{x - 3} * (5)(x + 6)(x - 3) = (25)(5)(x + 6) = 125(x + 6)


Now we put the pieces together.


Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)

5 0
3 years ago
Find the slope of the line passing through the points (-6-9) and (9,-9)
Otrada [13]

9514 1404 393

Answer:

  • zero
  • undefined

Step-by-step explanation:

The slope formula is useful for this.

  m = (y2 -y1)/(x2 -x1)

__

<u>First line</u>:

  m = (-9 -(-9))/(9 -(-6)) = 0/15 = 0

The slope of the first line is zero.

__

<u>Second line</u>:

  m = (-5-1)/(4 -4) = -6/0 = undefined

The slope of the second line is undefined.

_____

It is always a good idea to apply a little critical thinking to the given information. Here, you observe that the y-coordinates of the first pair of points are the same. That means this is a horizontal line, with a slope of 0.

Similarly, you observe that the x-coordinates of the second pair of points are the same. That means this is a vertical line, with undefined slope.

8 0
2 years ago
The original rectangle has a perimeter of 16
Serjik [45]

12.4 / 6.2 = 2

SF = 2

The original rectangle has a perimeter of 16

Perimeter of the enlarged rectangle = 16 x 2 = 32

Answer: 32 feet

6 0
3 years ago
Read 2 more answers
The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo
qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

5 0
3 years ago
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