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3 years ago

Evaluate. Write your answer as a fraction in simplest form. (4/3)2

Mathematics

2 answers:

Grace [21]3 years ago

8 0

Answer:

8/ 3

Step-by-step explanation:

Anna71 [15]3 years ago

5 0

Answer: 8/3

Step-by-step explanation: you would multiply the numerator (top number 4) by 2 and get 8/3 as a decimal it would be 2.6 repeated and as a mixed number it would 2 and 2/3

Hope this helps (^_^)

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3 years ago

Shane marched 3 m East and 6 m north. How far is he from his starting point. Round your answer to the nearest tenth.

Dennis_Churaev [7]

Answer:

The distance from his starting point is 6.7 m.

Step-by-step explanation:

Given:

Shane marched 3 m East and 6 m north.

Now, to get the distance from his starting point.

Let the distance from the starting point be $x.$

Now, to solve using pythagorean theorem:

$AB^2+BC^2=AC^2$

$6^2+3^2=x^2$

$36+9=x^2$

$45=x^2$

Using square root on both sides we get:

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3 years ago

AREA ADDITION AND SUBTRACTION ASSISTANCE?

Tom [10]

The shaded area is a segment. The area of a segment is

$A_{segment}=A_{sector}-A_{triangle}$ .

You know radius that is the side of isosceles triangle and measure of angle between two equal triangle sides, then

$A_{triangle} =\dfrac{1}{2} a\cdot a \sin \alpha=\dfrac{1}{2} 18.6\cdot 18.6 \cdot \sin 123^{\circ}=172.98\cdot \sin 123^{\circ}=145.07$ sq. m..

The area of sector is $A_{sector}=\dfrac{r^2\cdot \alpha}{2}= \dfrac{(18.6)^2\cdot 0.68\pi}{2}=117.63\pi=369.53$ sq. m..

Then $A_{segment}=369.53-145.07=224.46$ sq. m.

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