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Nimfa-mama [501]
3 years ago
6

Pls help (links will get reported)

Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

-938 ft

Step-by-step explanation:

the bird will be going down in elevation. the distance between -422 and -1360

-1360+422= -938

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Use the table to find the residual points. A 4-column table with 5 rows. The first column is labeled x with entries 1, 2, 3, 4,
Readme [11.4K]

Answer:

What is the change for each consecutive input?

✔ 1

What is the change for each consecutive output?

✔ 0.35

What is the rate of change for the relationship?

✔ 0.35

Step-by-step explanation:

The change for each input is 1 beacause the inputs are 10,11,12,13

The change for each consecutive output is 0.35 beacuse we need to subtract 4.1 from 3.75

The rate of change for the relationship is also 0.35

8 0
4 years ago
Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.
dezoksy [38]

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A <em>parallel</em> to vector B is defined by this formula:

\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b (1)

Where \|\vec b\| is the norm of vector B.

And the projection of vector A <em>perpendicular</em> to vector B is:

\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b} (2)

If we know that a = \langle -5, -1, 1 \rangle and \vec b = \langle -6, 0, 6 \rangle, then the projections are now calculated:

\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle

\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle

\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0
3 years ago
Neeed help 6x3+5-3x(-3)=?
butalik [34]

Answer:

32

Step-by-step explanation:

6 0
3 years ago
A corporation must appoint a president
adell [148]
A)11800
B)495
C).00202
3 0
3 years ago
Recall that two angles are complementary if the sum of their measures is 90. Find the measures of two complementary angles if on
dsp73

Answer: 25° and 65°

Step-by-step explanation:

Let the smaller angle of the complementary angle be represented by x.

Since the other angle is 15 degree more than two times the other angle, this will be:

= (2 × x) + 15°

= 2x + 15°.

Then we add both angles together and equate them to 90° and this will be:

x + 2x + 15° = 90°

3x + 15° = 90°

3x = 90° - 15°

3x = 75°

x = 75°/3

x = 25°

Then the other angle will be:

= 2x + 15°

= (2 × 25°) + 15°

= 50° + 15°

= 65°

Therefore, the angles are 25° and 65°.

8 0
3 years ago
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