Question

Factor P completely P(x) = x^4− 16

Answer 1

The factors of p(x) = $x^{4} -16$ are $(x^{2} -4) (x^{2} +4)$.

According to the question,

We have the following information:

p(x) = $x^{4} -16$

Now, we can solve this expression by using the identity. Now, the identity to be used here is $a^{2} - b^{2} = (a-b) (a+b)$.

(More to know: there are many identities which can be used to find the factors of an expression. There ae different ways to find the factors of an expression.)

In this case, the value of a is $x^{2}$ and the value of b is 4.

We can convert this fraction into this identity:

$(x^{2})^{2} -4^{2}$

So, we have the following expression:

$(x^{2} -4) (x^{2} +4)$

Hence, the factors of the given expression are $(x^{2} -4) (x^{2} +4)$.

To know more about factors here

brainly.com/question/24182713

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