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muminat

Look at it this way:

When you flip a coin, the probability of it landing with EITHER side showing
is 100%.

This leads us to the rule ...

The sum of the probabilities of
all possible outcomes is 100%.

For a coin: (probability of heads) plus (probability of tails) = 100%.

That just says: We're 100% sure that the coin will land with either
heads or tails up.

An "honest" coin gets heads 50% of the time and tails the other 50%.

But if the coin is all bent and squashed and has a feather stuck to
one side and a wad of gum on the other side so that it comes up
heads 70% of the time, then the coin isn't 'honest'. But it still has to
land EITHER heads OR tails, so the sum of the probabilities is still 100%.

So the probability of heads is 30%.

7 0

3 years ago

Assume a gasoline price of $3.55 per gallon. What is the gasoline cost for a 2000 mile trip if you drive at an average speed of

saul85 [17]

Answer:

The driving time at 54 miles per hour is 37.04 hours.

Step-by-step explanation:

8 0

3 years ago

There are blue, red and green pencils in the box—20 pencils total. There are 6 times more green pencils than blue pencils. There

lana [24]

Answer:

You have to take 15 pens to get at least one red pencil.

Step-by-step explanation:

If there were one red and 6 green pens, there would be more red than green pens.

If there were 3 or more blue and thus 18 or more green pens, the number of pens would be over 20.

So there must be 2 blue, 12 green and thus 6 red pencils. So you have to take at least 15 pens to be sure that you got a red one.

5 0

3 years ago

.<br><br> 26.<br> Solve 3(2+1) +11 <-2(2 + 13).

ruslelena [56]

Answer:

its 9 sorry if its wrong

3 0

3 years ago

Daily-high temperature measurements for 40 consecutive days are recorded for a particular city. The mean daily-high temperature

Vesnalui [34]

Answer:

$t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108$

$p_v =P(t_{39}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation

$\bar X=21.5$ represent the mean for the temperatures

$s=1.5$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =22$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:

Null hypothesis: $\mu \geq 22$

Alternative hypothesis: $\mu < 22$

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108$

P-value

We can calculate the degrees of freedom like this:

$df=n-1=40-1=39$

Since is a one left tailed test the p value would be:

$p_v =P(t_{39}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

5 0

3 years ago

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brainliest brainliest brainliest help me for ut