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Aleksandr-060686 [28]
3 years ago
9

The total cost in dollars for Larry to have his birthday party at a local

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

0 \leq p < 6

Step-by-step explanation:

Given

t = 6.95p + 29.95

Amount = 70

Required

Determine the domain

First, we need to solve for p

Substitute 70 for t in t = 6.95p + 29.95

70 = 6.95p + 29.95

Collect Like Terms

6.95p = 70 - 29.95

6.95p = 40.05

Solve for p

p = 40.05/6.95

p = 5.76

This implies that Larry can not invite up to 6 people.

Hence, the domain can be represented as: 0 \leq p < 6

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The population of a country was increased in the past 4 years. The annual presentage increases are 20%,25%,30%,10% respectively.
Vladimir79 [104]

The answer is 114.5%.

Let the original population be denoted by x.

Now, let's go through the percentage increase per year.

<u>Year 1</u>

  • x (1 + 20%)
  • x (1.2)
  • 1.2x

<u>Year 2</u>

  • 1.2x (1 + 25%)
  • 1.2x (1.25)
  • 1.5x

<u>Year 3</u>

  • 1.5x (1 + 30%)
  • 1.5x (1.3)
  • 1.95x

<u>Year 4</u>

  • 1.95x (1 + 10%)
  • 1.95x (1.1)
  • 2.145x

Overall increase : 214.5% - 100% = 114.5%

Hence, the overall percentage increase in these 4 years is 114.5%.

7 0
1 year ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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3 years ago
Help would be greatly appreciated!Which equation is true?
Serga [27]

Answer:

Step-by-step explanation:

(edit):

lol this post was an accident, mb

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2 years ago
Solve:-<br><br> 7^5<br><br> Thanks!!!!!!!!!!!!!
solong [7]
These are exponents. To solve an exponent you need to multiply the base it self how many times its says in the power.

a² 

a = base
<span>2 = power
</span>
7^5 = 7 × 7 × 7 × 7 × 7 = <span>16807
7^5 = </span><span>16807</span>
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