X = 3
10 + 12x = 15x + 1
10 = 3x + 1
9 = 3x
3 = x
Answer:
a) If a key is selected at random, what is the probability that the key for channel 1 is pressed?
1/10
<em>There are 10 channels in total. 9 channels + 0 channel. </em>
<em />
b) If a key is selected at random, what is the probability that the key for an even number is pressed?
5/10
0,2, 4, 6, 8 < The even numbers out of 10 channels
c) If a key is selected at random, what is the probability that the key for a number more than 6 is pressed?
3/10
<em>7, 8, 9 are the numbers greater than 6</em>
<em>
</em>
<em />
<em />
<em />
<em />
<em />
<em />
(x+y-3)(x+y+3) = x^2+xy+3x+xy+y^2+3y-3x-3y-9 = -9+x^2+y^2+2xy
It would be from 0 < x < 4 as the question is basically asking when is the function below the y value of 0, so below the x-axis
Answer:
Step-by-step explanation:
Last season two running backs on the Steelers football team rushed a combined total of 1550 yards. One rushed 4 times as many yards as the other. Let x and y represent the number of yards each individual player rushed. this is the equation that was used
x + y = 1550
y = 4x
