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3 years ago

What is the solution to x?

Mathematics

1 answer:

Sonja [21]3 years ago

3 0

Answer:

Step-by-step explanation:

By geometric mean theorem,

In a triangle ABC,

$\frac{BC}{AC}=\frac{CD}{BC}$

$\frac{y}{(4+6)}=\frac{6}{y}$

y² = 60

y = √60

y = 7.75

Similarly, $\frac{AB}{AC}=\frac{AD}{AB}$

$\frac{x}{(4+6)}=\frac{4}{x}$

x² = 40

x = √40

x = 6.32

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3 years ago

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Function- f(x)=-x^2+4x+6

anygoal [31]

Answer:

At the positive integer value of x=7 the quadratic function begin to exceed the linear function

Step-by-step explanation:

we have

using a graphing tool

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For x < -1.405 and x > 6.405 the quadratic function begin to exceed the linear function

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3 years ago

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of

GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.989.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

$M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23$

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

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3 years ago

Line M is represented by the following equation x - y = 7 which equation completes the system that is satisfied by the solution

irina1246 [14]

Answer:

Step-by-step explanation:

17-10=27-7=

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2 years ago

Oblicz.Pamiętaj o kolejności wykonywania działań

SashulF [63]

Answer:

33.275

Step-by-step explanation:

1 step: Difference in brackets

$3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}$

2 step: $0.75\div\dfrac{1}{3}$

$0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}$

3 step: $1.28\div 0.04$

$1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}$

4 step:

$2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}$

5 step:

$\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275$

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2 years ago

What is the solution to x?​

What is the solution to x?