Answer:
Step-by-step explanation: Given : f(x)=x
4
−3x
2
+4
f(2)=(2)
4
−3(2)
2
+4
=16−12+4=8
Slope
-9+7 -2
—— = ——
-5+10 5
Equation of a line
y+7=-2/5(x+10)
y+7=-2/5x-4
y=-2/5x-11
Answer:
0.527
Step-by-step explanation:
From the question,
The sequence is Geometry Progression (G.P)
Tₙ = arⁿ⁻¹.......................... Equation 1
Where n = number of term, a = first term, r = common ratio
Given: n = 7, a = 6, r = 2/3
Substitute these values into equation 1
T₇ = 6(2/3)⁷⁻¹
T₇ = 6(2/3)⁶
T₇ = 6(64/729)
T₇ = 384/729
T₇ = 0.527
Hence, the 7th term of the sequence is 0.527
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Answer:
y = -0.07x2 + 3.07x
Step-by-step explanation:
For each plant we add, there is a decrease of 70 grams for all plants from the inicial value of 3 kg of beans.
So, for 2 plants, we have (3 - 0.07) * 2
For 3 plants, we have (3 - 2*0.07) * 3
For x plants, we have (3 - (x-1)*0.07) * x
So we can model the final result of the amount of beans 'y' with the equation:
y = (3 - (x-1)*0.07) * x
y = (3 - 0.07x + 0.07) * x
y = (3.07 - 0.07x) * x
y = -0.07x2 + 3.07x
(In this equation we have a = -0.07, b = 3.07 and c = 0)