Answer:
Find below the calculations of the two areas, each with two methods. The results are:


Explanation:
<u>A) Method 1</u>
When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

Where,
is the measure of the included angle.
1. <u>Upper triangle:</u>

2. <u>Lower triangle:</u>

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<u>B) Method 2</u>
You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

Use it for both triangles.
3. <u>Upper triangle:</u>
The trigonometric ratio that you can use is:

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:


3. <u>Lower triangle:</u>
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Answer:
A 2√2(cos 7π/4 + i sin 7π/4)
Step-by-step explanation:
A. 2√2(cos 7π/4 + i sin 7π/4)
2 sqrt(2) ( sqrt(2)/2 - sqrt(2)/2 i)
Distribute
2-2i
This is in the fourth quadrant
B. 2√2(cos 150° + i sin 150°)
2 sqrt(2) (-sqrt(3)/2 +1/2i)
-sqrt(6) +sqrt(2) i
This is in the third quadrant (NO)
C. 2(cos 7π/4 + i sin 7π/4)
2( ( sqrt(2)/2 - sqrt(2)/2 i))
sqrt(2) - sqrt(2) i
This is the fourth quadrant
D. 2(cos 90° + i sin 90°)
2(0+i)
2i
This is on the positive y axis NO
Now we need to decide between the two in the fourth quadrant.
The point has an x coordinate of 2 and a y coordinate of -2
This aligns with point A
Step-by-step explanation:
a)
Two of the three interior angles are known. Both are equal to 55°. This can be seen by looking closely at the picture. To find the third angle subtract the other two from 360°

b)
Do the same thing only afterward subtract the third angle from 180 to find the supplementary angle

Answer:
16q + 32r
Step-by-step explanation: