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borishaifa [10]
2 years ago
7

At a bargain store, Tanya bought three items that each cost the same amount. Tony bought four items that each cost the same amou

nt, but each was $2.25 less then the items that Tanya bought. Both Tanya and Tony paid the same amount of money. What was the individual cost of each person's items?
Mathematics
1 answer:
djverab [1.8K]2 years ago
5 0
Each of Tony’s items are $7.65
Each of Tanyas items are $10.2
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Graph the line that is parallel to y = 3x - 7 that passes through the point (2, 1)
Misha Larkins [42]

Answer:

y = 3x - 5

y = 3x - 7

y = 3x + b

1 = 3(2) + b

1 = 6 + b

-5 = b

y = 3x - 5

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3 years ago
When the point (-3,2) is reflected across the y-axis, what are the coordinates of the resulting point?
Elanso [62]
The new point would be at (3,2)
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1 year ago
In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.
Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

j = \sqrt{99.45}

j = 9.97

∴

\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}

{9.97 \times    Sin (L ) = (2.7 \times Sin \ 43)

=  Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ =  Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 }  \\ \\  = Sin \ L = 0.18466 \\ \\  L = Sin^{-1} (0.18466) \\ \\  L = 10.64 ^0

3 0
2 years ago
Which equation is equivalent to √x^2+81 = x+10
jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2

By definition:(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100

Thus, x ^ 2 + 81 = x ^ 2 + 20x +100 is equivalent to \sqrt {x ^ 2 + 81} = x + 10

Answer:

x ^ 2 + 81 = x ^ 2 + 20x +100

Option D

4 0
3 years ago
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