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2 years ago

Valence electrons are the number of

Chemistry

2 answers:

netineya [11]2 years ago

6 0

Number of electrons on the outside

jenyasd209 [6]2 years ago

4 0

Answer:

an be found by determining the electronic configurations of elements. Thereafter the number of electrons in the outermost shell gives the total number of valence electrons in that element.

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The combustion reaction of magnesium results in what compound?

Tasya [4]

C. MgO because mg+o= MgO

7 0

2 years ago

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2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way

sasho [114]

Answer: 7.98 grams of $Fe_2O_3$ are produced if 10.7 grams of $Fe(OH)_3$ are reacted.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Putting values in equation 1, we get:

$\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol$

The chemical equation for the reaction is

$2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O$

By Stoichiometry of the reaction:

2 moles of $Fe(OH)_3$ produce = 1 mole of $Fe_2O_3$

So, 0.100 moles of $Fe(OH)_3$ produce= $\frac{1}{2}\times 0.100=0.05mol$ of $Fe_2O_3$

Mass of $Fe_2O_3$ = $moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g$

Hence 7.98 grams of $Fe_2O_3$ are produced if 10.7 grams of $Fe(OH)_3$ are reacted.

3 0

2 years ago

The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c

netineya [11]

Answer: The solubility of oxygen at 682 torr is $4.58\times 10^{-3}M$

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of oxygen gas

$C_2\text{ and }p_2$ are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used: 1 atm = 760 torr

$C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm$

Putting values in above equation, we get:

$\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M$

Hence, the solubility of oxygen gas at 628 torr is $4.58\times 10^{-3}M$

4 0

2 years ago

use the equation 2C4H10 +13O2-->8CO2+10H2O to find how many moles of oxygen would react with .425 mol C4H10

antoniya [11.8K]

2C4H10 + 13O2 → 8CO2 + 10H2O Since the equation is balanced, we can set up a proportion: 13 moles of O2 react with 2 moles of C4H10x moles of O2 react with 0.425 moles of C4H10 13 → 2x → 0.425 x = 13 * 0.425 / 2 = 2.7625 2.7625 moles of O2 react with 0.425 moles of C4H10

6 0

2 years ago

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1. What is a food web?

Anuta_ua [19.1K]

Answer:

a producer and consumer relationship how several food chains and related.

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2 years ago

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