Answer:
- <u><em>Saturated</em></u>
<u><em></em></u>
Explanation:
Translation:
- <em>50 grams of solute at room temperature in a 100ml container of water, but the solute accumulated at the bottom. He heated it allowing it to dissolve just an additional 10 grams of solute. What solution did you get? Oversaturated, unsaturated, saturated or diluted</em>
<em />
<h2>Solution</h2>
A<em> saturated</em> <em>solution</em> contains the maximum amount of solute that it can dissolve at the given temperature and pressure.
If you add more solute than that it will not get <em>dissolved</em> but the extra solute will remain as a solid at the<em> bottom</em> of the <em>solution</em>.
The fact that, for the <em>solution</em> with 50 grams of solute, the <em>solute accumulated</em> at the <em>bottom</em> means that it could not dissolve more, so the solution was saturated.
By <em>heating</em> the solution it was able to <em>dissolve</em> more <em>solute </em>but the fact that yeat some <em>grams</em> were undissolved means that the solution was still saturated at the new temperature.
<em>Oversaturated</em> is an unstable state at which the solution can dissolve more solute than what the normal solubility permits. That state can be reached only under special procedures which would require a different description.
Thus, you get a <em>saturated solution</em>.
The empirical formula is C₇H₆O₂.
Assume that you have 100 g of the compound.
Then you have 68.84 g C and 4.962 g H.
Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.
Now, we must convert these masses to moles and find their ratios.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u> ×2</u> <u>Integers</u>
C 68.84 5.732 3.501 7.001 7
H 4.962 4.923 3.006 6.012 6
O 26.20 1.638 1 2 2
The empirical formula is C₇H₆O₂.
Answer:
Explanation:
See attached table.
Note that:
1 mole = 6.02x10^23
Molar mass is grams/mole. For the elements, the atomic mass is the same number as molar mass, just expressed as grams/mole.
<span>362.51 Kelvin
ln (p1/p2) =( dH / R) (1/T2 - 1/T1)
ln (760 Torr /520Torr) =( 40,700 Joules / 8.314 J molâ’1K-1)(1/T2 - 1/373K)
ln (1.4615) =( 4895.35)(1/T2 - 0.002681)
0.37946 = 4895.35/T2 - (0.002681)(4895.35)
0.37946 = 4895.35/T2 - (13.124)
0.37946 + 13.124 = 4895.35/T2
13.5039 = 4895.35/T2
T2 = 4895.35 / 13.5039
T2 = 362.51
answer is 362.51 Kelvin
- 273
answer is also 89.5 Celsius</span>
