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Art [367]
2 years ago
8

In an experiment, the same mass of magnesium metal reacted with the same amount of two different acids. the acid used in reactio

n 1 was ethanoic acid and in reaction 2 it was hydrochloric acid. which reaction produced the most gas?
Chemistry
1 answer:
denpristay [2]2 years ago
6 0

The mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

<h3>What is the mole ratio of a reaction?</h3>

The mole ratio of a reaction is the ratio in which the reactants and products of a given reaction occur for the reaction to proceed to completion.

The mole ratio of a reaction is also known as the stoichiometry of the reaction.

The equation of the two reactions are given below:

Mg + 2HCl \rightarrow MgCl_2 + H_2

Mg + 2CH_3COOH \rightarrow (CH_3COO)_2Mg + H_2 \\

From the equation of the reaction reaction, an equal volume of hydrogen gas will be produced by the two reactions.

Therefore, the mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

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Identify which one is the reducing agent in this reaction
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Answer:

Na.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
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  • For the reaction:

<em>2Na + S → Na₂S.</em>

<em></em>

Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".

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6 0
3 years ago
A sample of metal has a mass of 23.04 g, and a volume of 5.31 ml. what is the density of this metal?
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5 0
3 years ago
Na3po4 dissolves in water to produce an electrolytic solution. what is the osmolarity of a 2. 0 × 10-3 m na3po4 solution?
vichka [17]

When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.

Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.

In other words osmolarity is the multiple if molarity

Osmolarity = i× molarity

Here i represents the van't Hoff factor,

Na_{3}PO_{4} ⇒ 3Na^{+} + PO_{4} ^{-}

3  Moles of Na_{} ^{+} + 1 mole PO_{4} ^{-} = 4

The number of moles of particles of solute produced in solution are actually called osmoles.

As a result, the van't Hoff factor will be equal to

i=4 Moles ions produced (osmoles) 1mole Na_{3} PO_{4} .dissolved =4

Since we know that,

Na_{3} PO_{4} = 2.0 * 10^{-3} M

Osmolarity =

4*2.0*10^{-3} M = 8.0 * 10^{-3}  osmol L -10s

Thus, the Osmolarity of given solution is 0.008 osmol/L.

learn more about Osmolarity:

brainly.com/question/13597129

#SPJ4

6 0
2 years ago
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