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vitfil [10]
3 years ago
6

Calculate the frequency of electromagnetic wave with the wave length 344nm ( hint: use dimensional analysis)

Chemistry
1 answer:
Svetlanka [38]3 years ago
5 0
Frequency = speed of light
                      ---------------------------
                        wavelength 
 
                   =        3 x 10^8
                      ------------------------
                          344 x 10^-9
 
                   =          8.72 x 10^14 Hz.

Hope this helps!



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Scientists make observations, conduct experiments, and draw conclusions. Which statement is true of all scientists?
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Answer:

study the natural world

7 0
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How many moles of ethanol are produced starting with 500.g glucose?
Monica [59]
<h3>Answer:</h3>

5.55 mol C₂H₅OH

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

[Given] 500. g C₆H₁₂O₆ (Glucose)

[Solve] moles C₂H₅OH (Ethanol)

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH

[PT] Molar mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up conversion:                                                                                 \displaystyle 500 \ g \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{180.18 \ g \ C_6H_{12}O_6})(\frac{2 \ mol \ C_2H_5OH}{1 \ mol \ C_6H_{12}O_6})
  2. [DA} Multiply/Divide [Cancel out units]:                                                         \displaystyle 5.55001 \ mol \ C_2H_5OH

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH

8 0
3 years ago
student in chemistry 150-02 weighed out 55.5g of octane c8h18 and allowed it to react with oxygen, o2 the product formed were ca
Tasya [4]

Answer:

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Explanation:

unbalanced reaction:

C8H8 + O2 → CO2 + H2O

balanced for semireactions:

(1) 16H2O + C8H8 → 8CO2 + 40H+

(2) 10(4H+ + O2 → 2H2O)

⇒ 40H+ + 10O2 → 20H2O

(1) + (2):

balanced reaction:

⇒ C8H8 + 10O2 → 8CO2 + 4H2O

                      8 - C - 8

                     20 - O2 - 20

                      8 - H - 8

3 0
3 years ago
elements on the right side of the periodic table differ from the elements on the left side in that elements on the right side
yarga [219]

Element  on the right side  of the periodic  table  differ from the elements on  the left side  in that elements on the <em>right  side  are non   metallic  and tends to be gases at room  temperature.</em>


<em>  </em><u>Explanation</u>

In the periodic table there element in  the right side , left side and those  which are in between.

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  • there electrostatic  intermolecular  forces  are generally weak  therefore they  exist in  liquid or gaseous state.
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What is the scientific notation of 68000
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3 0
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