Answer:
-See below
Step-by.step explanation:
In the first column, on the left of the vertical line, you place the first digit of the number , then on the second row on you place the second digit.
So on the second row you have the entries:
1 | 2 2 4 representing 12, 12 and 14.
On the first row the 2 0ne digit numbers 3 and 8 are represented by
0 | 3 8.
Similarly the last 2 rows are:
2 | 0 1 3 6
3 | 4
As a decimal it is 4.875.
The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
<h3>What are permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
It is given that:
On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:
The required number of ways:
= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))
= 2[2[ 1 + 5 + 15+35] + 70]
= 364
Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
Learn more about permutation and combination here:
brainly.com/question/2295036
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Answer:
2×π×(1/2)L×L+2×π×((1/2)L)^2
Step-by-step explanation:
perimeter of cross-section × height +2× area of cross-section
