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suter [353]
3 years ago
15

Parallel lines t and u are cut by two transversals, r and s, which intersect line u at the same point.

Mathematics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:

D

Step-by-step explanation:

it was right on edge

Lelu [443]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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What is the maximum point OR minimun point of this equation?
Setler79 [48]
Answer is 3 because when you solve its 3 or less
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3 years ago
Find the midpoint M of the two sets of points. (Use midpt. formula)
Setler79 [48]
3.5,1.75
7/2,3.5/2
Those 2
5 0
2 years ago
The polynomial $f(x)$ has degree 3. If $f(-1) = 15$, $f(0)= 0$, $f(1) = -5$, and $f(2) = 12$, then what are the $x$-intercepts o
Alex_Xolod [135]

Your calculator's cubic regression function can tell you the equation is

... f(x) = 2x³ + 5x² -12x = x(x +4)(2x-3)

The x-intercepts are -4, 0, +1.5.

_____

If you want to solve this "by hand", you can first of all recognize that since there is an x-intercept at 0, the cubic will only have three coefficients. That is, you can write the equation as

... f(x) = ax³ + bx² + cx

Substituting the given points (except (0, 0)) gives three linear equations in a, b, c.

... -a +b -c = 15 . . . . . for x=-1

... a + b + c = -5 . . . . for x=1

... 8a +4b +2c = 12 . . for x=2

adding the first two equations gives 2b=10, or b=5. Now, you can reduce the system to

... a + c = -10

... 4a +c = -4

Subtracting the first of these equations from the second gives 3a=6, or a=2. That tells you c=-12 (from a+c=10).

Then your equation is

... f(x) = x(2x² +5x -12)

Factoring by any of the usual techniques, or graphing, or using the quadratic formula will tell you the zeros (x-intercepts) are as above.

_____

Since the input values are sequential, you can also develop the function from differences of the output values. Those are 15, 0, -5, 12. First differences are -15, -5, +17. Second differences are +10, +22. The third difference is 12. Using the first of these differences in appropriate places in the interpolating polynomial formula, we have

... f(x) = 15 + (x+1)(-15 + (x)/2·(10 + (x-1)/3·(12))) = 2x³ +5x² -12x . . . . as above

4 0
3 years ago
How do I find x? Do I find the hypotenuse of 15 and 18, then with that answer minus it by 22^2 in a root?
pogonyaev
8+x= \sqrt{22^2-15^2} => 8+x = 15 => x = 15-8=7
7 0
4 years ago
WILL MARK BRAINLIEST PLEASE HELP
Serga [27]
It’s the second one, 65.4

V=1
6πd3=1
6·π·53≈ 65.44985in³
7 0
3 years ago
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