1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lukranit [14]
3 years ago
15

Find the slope of the line that passes through the points (2,4) and (6,12)?

Mathematics
2 answers:
Illusion [34]3 years ago
7 0

Answer:

2 hurry!

Step-by-step explanation:

saw5 [17]3 years ago
4 0

Answer:

m=2

Step-by-step explanation:

y2-y1/x2-x1

12-4/6-2

=8/4=2

m=2

You might be interested in
Please answer this asap
Advocard [28]

Answer:

yall jits be tweakin with that stealing ppl answers s h i

Step-by-step explanation:

6 0
3 years ago
-2(n+3 = -12
Blizzard [7]

Answer: n=3

Step-by-step explanation:

Divide by - 2

(N+3) = 6

Subtract 3

N= 3

6 0
3 years ago
Read 2 more answers
If CD is the perpendicular bisector of AB, then the value of X is:
Cloud [144]
AC side and BC side have the same length because ΔCDA and ΔCDE are congruent.

The equation will be
AC = BC

Solve the equation
AC = BC
2x = 3x - 10
2x - 3x = -10
-x = -10
x = 10

The value of x is 10
4 0
4 years ago
Find the mean absolute deviation of the following numbers. 10, 8, 5, 12, 20
kicyunya [14]
The mean absolute deviation of the following set of data is 4.5
Step-by-step explanation:
We need to find the mean absolute deviation of the following set of data.
10,20,12,4,18,8,14,18
For finding mean absolute deviation, first we need to find the mean of the given data set.
The formula used to calculate mean is:
Sum of all data points: 10+20+12+4+18+8+14+18 = 104
Number of data points = 8
So, mean is:

Now, we will subtract 13 from the given data points:
10 - 13 = -3
20 - 13 = 7
12 - 13 = -1
4 - 13 = -9
18 -13 = 5
8 - 13 = -5
14 - 13 = 1
18 - 13 = 5
We will take absolute values i.e |-a|=a
So, now the numbers will be:
3,7,1,9,5,5,1,5
We will now find absolute mean deviation by finding mean of newly calculate values
Sum of all data points = 3+7+1+9+5+5+1+5
Number of data points = 8

So, the mean absolute deviation of the following set of data is 4.5
4 0
3 years ago
Factor completely 8x5 2x4 4x2. Prime 2(4x5 x4 2x2) 2x(4x4 x3 2x) 2x2(4x3 x2 2).
Alecsey [184]

The complete factor of the expression \rm 8x^5 + 2x^4 + 4x^2 is \rm 2x^{2} (4x^3 + x^2 + 2 )correct option is D.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is \rm 8x^5 + 2x^4 + 4x^2.

To solve the expression properly we have to take common (2x²). Then we have

\rm 8x^5 + 2x^4 + 4x^2\\\\2x^{2} (4x^3 + x^2 + 2 )

The factor is \rm 2x^{2} (4x^3 + x^2 + 2 ).

More about the factorization link is given below.

brainly.com/question/6810544

4 0
2 years ago
Other questions:
  • The following items are in the shape of a square. How many squares are
    7·2 answers
  • Determine consecutive integer values of x between which each real zero is located.
    13·1 answer
  • Is it true that, the opposite of zero is zero.
    11·2 answers
  • The owner of a greenhouse wants to test the effectiveness of a new fertilizer on African violets. She has 60 violet seedlings th
    9·1 answer
  • Solve the system of linear equations by substitution.<br><br> 4x−2y=14<br> y=0.5x−1
    13·1 answer
  • 1^2 + 4^2 + 7^2 -... - (3n - 2)^2 = n(6n^2 - 3n - 1)/2
    15·1 answer
  • PLEASE PLEASE HELP ME !!!i need to solve this doing the zero product property
    13·1 answer
  • Meghan ran nine twelfths of a mile and skipped eight twelfths of a mile around a track. How far around the track did Megan go in
    5·2 answers
  • Please help! 50 points!
    12·1 answer
  • The following list gives the number of public libraries in each of 14 cities.7, 4, 5, 4, 5, 4, 4, 7, 8, 4, 6, 6, 6, 5Find the mo
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!