Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
C. Cytology is the study of cells, while histology is the study of tissues
Explanation:
Just learned about cytology, and searched up histology, and it is about tissues. Every other answer is wrong.
Hope this helped :)
Answer:
it might catch to much sun with black petals or no sun at all with none so in other words it would probably die.
Explanation:
white reflects heat, black attracts heat
Answer:
Option A
Explanation:
Undigested fats include all those fatty acid and lipids which do not have the ability to dissolve in water. This inability makes them difficult elements for digestion. All this undigested fat accumulates and reaches the intestine for digestion as globs. Globs are emulsified by the bile salts and are broken down into smaller fat droplets. The smaller fat droplets have large surface area and hence now they can be acted upon by the fat-digesting enzyme pancreatic lipase. Thus, the first set of enzymes that act upon the undigested fats in the intestine are pancreatic lipase
Hence, option A is correct
Answer:
A. A prokaryote lacks a well-defined nucleus.
C. A prokaryote lacks cell organelles.
Explanation:
A prokaryote has DNA or RNA just floating in the cytoplasm. There is no nucleus to hold them inside. A prokaryote also lacks a mitochondria and other organelles, so it is different from a eukaryote.