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andrew11 [14]
3 years ago
14

At one point the average price of regular unleaded gasoline was $3.57 per gallon. Assume that the standard deviation price per g

allon is $0.05 per gallon and use Chebyshev's inequality to answer the following. (a) What percentage of gasoline stations had prices within 4 standard deviations of the mean? (b) What percentage of gasoline stations had prices within 2.5 standard deviations of the mean? What are the gasoline prices that are within 2.5 standard deviations of the mean? (c) What is the minimum percentage of gasoline stations that had prices between $3.47 and $3.67?
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0
I don’t know the answer for that I will try to work out this problem
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A

Step-by-step explanation:

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What is −20÷45−20÷45 ?<br><br><br> A. −25<br><br> B. −16<br><br> C− 1/16<br><br> D. − 1/25
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A total of 133 million square miles of the Earth's surface are covered in water. The ratio of the area covered in water to the a
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Step-by-step explanation:

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2 years ago
The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
vodka [1.7K]
So there are 3 siblings: the first twin, the second twin, and their older sister.

Since the sister is older by 11 years, you can represent their relationship with the following equation;
age of twin = age of older sister - 11
t = s - 11

Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
total age = t + t + s
If the product of their ages ( t * t * s ) is 1181 more than the sum, you can show it like this:
t * t * s = (t + t + s) + 1181
Now you substitute in (s - 11) for t because s = t - 11.
t * t * s = (t + t + s) + 1181\\&#10;(s-11) * (s-11) * s = ((s-11) + (s-11) + s) + 1181\\&#10;(s^{2}-22x+121)*s=s+s-11-11+1181\\&#10;s^{3}-22s^{2}+121s-2s=1159\\&#10;s^{3}-22s^{2}+118s-1159=0
Factor:
Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
s^{3}-22s^{2}+118s-1159=0\\&#10;(s-19)(s^{2}-3s+61)=0
Using the quadratic formula, you get:
s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\&#10;s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\&#10;s= \frac{3(+-)\sqrt{(9)-244}}{2}\\&#10;s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
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