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dsp73
3 years ago
9

Help! Or my mums gonna kill me!

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

You haven't explained what you need help with! :) you have to be specific in times of life and death

Step-by-step explanation:

swat323 years ago
6 0

Answer:

With what?

Step-by-step explanation:

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4) From a graphed linear line, how do you find the<br> Slope:<br> Y-intercept:
Ad libitum [116K]

Rise over Run

Put the amount you go up or down on the Y-axis over how much you go right or the x-axis

the Y-intercept is found simply by looking where the graph crosses the y, if the equation is written instead of graphed, graph it using a graphing calculator, then use the information I gave you previously : )

8 0
3 years ago
Which solid has two triangular bases and three lateral faces, each in the shape of a rectangle?
MaRussiya [10]

Answer: answer C is correct

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Pls help meee<br>thank you thank you thank you thank you
olga_2 [115]

Answer:

See below

Step-by-step explanation:

11 box 1: 12

11 box 2: 101

12 box 1: 80

12 box 2: 80

12 box 3: 80

13 box 1: 16

13 box 2: 16

13 box 3: 76


20 = y + 12

20 - 12 = y + 12 - 12

8 = y


x + 2 = 19

x + 2 - 2 = 19 - 2

x = 17


z - 313 = 176

z - 313 + 313 = 176 + 313

z = 489

6 0
3 years ago
Read 2 more answers
If one-half of a number decreased by 20 is 40, what is the number?
Anvisha [2.4K]

Answer:

120

Step-by-step explanation:

Just add the 20 back to 40 and times by 2

40 + 20 = 60

60 * 2 = 120

8 0
2 years ago
Read 2 more answers
Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30
Dafna11 [192]
Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

\bf u=&#10;\begin{cases}&#10;x=7cos(330^o)\\&#10;\qquad 7\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{7\sqrt{3}}{2}\\&#10;y=7sin(330^o)\\&#10;\qquad 7\cdot -\frac{1}{2}\\&#10;\qquad -\frac{7}{2}&#10;\end{cases}\qquad \qquad v=&#10;\begin{cases}&#10;x=8cos(30^o)\\&#10;\qquad 8\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{8\sqrt{3}}{2}\\&#10;y=8sin(30^o)\\&#10;\qquad 8\cdot \frac{1}{2}\\&#10;\qquad 4&#10;\end{cases}

\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)&#10;\\\\\\&#10;\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~  \stackrel{b}{\frac{1}{2}}\right)\\\\&#10;-------------------------------

\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}&#10;\\\\\\&#10;\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o
8 0
3 years ago
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