Answer: 35
Step-by-step explanation:
Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
The probability to choose letter n is
. After drawing letter n there left 25 letters and the probability to choose the letter w is
. After drawing two letters n and w there left 24 letters and then the probability to choose letter b is
. After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is
.
Using the product rule for probabilities, you can obtain that
.
The height is 1, because it's A=(b1 + b2)*h, the equation is this now 7=3 + 4)*h, you add 3 + 4 then that will give you 7, so now it should look like this 7=7*h, you do a fraction line under the 7 and 7*h each, and put a 7 as the denominator, so it kind of looks like this now 7 = 7*h
__ __
7 7 then you cancel the 7*h which leaves you to just h, so 7 divided by 7 will give you 1 so it looks like 1=h, PHEW
