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tatuchka [14]
3 years ago
13

What is the slope of the line shown?

Mathematics
2 answers:
Sonbull [250]3 years ago
6 0
I think the answer is -1/3
sashaice [31]3 years ago
3 0
The slope would be -1/3
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Use Pascal's Triangle to determine the second term of the expansion of (x - 2)^5
goldfiish [28.3K]

Pascal's triangle up to the 5th iteration is

\begin{array}{cccccc}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\\1&5&10&10&5&1\end{array}

This tells us

(x-2)^5=\boxed{1}x^5(-2)^0+\boxed{5}x^4(-2)^1+\boxed{10}x^3(-2)^2+\boxed{10}x^2(-2)^3+\boxed{5}x^1(-2)^4+\boxed{1}x^0(-2)^5

so the second term in the expansion is

5x^4(-2)^1=\boxed{-10x^4}

8 0
3 years ago
3927283+8093<br> Help pls
Debora [2.8K]

Answer: 3935376

Step-by-step explanation: 3927283+8093

3935376

7 0
2 years ago
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PLEASE HELP! Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.
valina [46]

5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5

6 0
3 years ago
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Can i please have help with number 6
Allisa [31]
Length of the diameter =   sqrt ( (-12- (-8)^2) +(2-0)^2) )
  = sqrt  (16 + 4) = sqrt20 
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5


Center of the circle = coordinates of the midpoint of the diameter =

-8-12/2 , 2-0 / 2  =    (-10, 1)

(x - a)^2 + (y - b)^2 = r^2  is general form of a circle so here the circle is:_

(x + 10)^2 + (y - 1)^2 = 5  Answer

Its B
7 0
2 years ago
In ∆ KLM above, NO // ML and &lt; KNO = &lt; KON. Find m &lt; MNL =
4vir4ik [10]

Answer: In ∆ KLM above, NO // ML and < KNO = < KON. Find m < MNL =

Step-by-step explanation: dUNNO

6 0
2 years ago
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