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2 years ago

HELP PLEASE ANSWER 7

Mathematics

1 answer:

ololo11 [35]2 years ago

7 0

Answer:

f(x) = 7

Step-by-step explanation:

we use the bottom equation (4x+3) because

1 > 0

4(1) +3 = 7

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What is 3.78 × 10 ²=

Anika [276]

Answer:

3.78 × $10^{2}$ = 378

Step-by-step explanation:

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2 years ago

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What are the x and y-intercepts of the line described by the equation?

tatuchka [14]

Answer: x=4.41 y= -7.35

Step-by-step explanation:

Pretty basic just graph them using Desmos...

Showing your work you would need to get x on one side then y on the other.

Because 3y is positive I personally like to use that one first. The inverse operation of 3y is divide so you divide 3y by 3 and the 3s cancel out. Divide -22.05 by 3 and you get -7.35. Which is your y value.

Finding X is a bit more difficult, you need to divide by -5 which is the obvious inverse operation. So, -22.05/-5 and you get 4.41. Which is your X value.

Any further questions feel free to contact me.

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2 years ago

How do I solve writing systems of equations in Algebra 1?

melisa1 [442]

Let books =x and games =y
2x+2y=26
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2 years ago

Find the differential of each function. (a) y = tan( 7t ) dy = Incorrect: Your answer is incorrect. (b) y = 4 − v2 4 + v2 dy =

Kisachek [45]

Answer:

$(a) dy= 7sec^2(7t)dt\\\\(b) dy = \frac{-16v}{(4+v^2)^2} dv$

Step-by-step explanation:

Given;

(a) y = tan (7t)

let u = 7t

y = tan(u)

du/dt = 7

dy/du = sec²(u)

$\frac{dy}{dt} = \frac{dy}{du} *\frac{du}{dt}\\\\\frac{dy}{dt} = sec^2(u)* 7\\\\\frac{dy}{dt} =7sec^2(u)\\\\\frac{dy}{dt} = 7sec^2(7t)\\\\dy = 7sec^2(7t)dt$

(b)

$y = \frac{4-v^2}{4+v^2}\\\\$

let u = 4 - v²

du/dv = -2v

let v = 4 + v²

dv/du = 2v

$y = \frac{4-v^2}{4+v^2}\\\\\frac{dy}{dv} = \frac{vdu-udv}{v^2} \\\\\frac{dy}{dv} =\frac{-2v(4+v^2)-2v(4-v^2)}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-8v-2v^3-8v+2v^3}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-16v}{(4+v^2)^2}\\\\dy = \frac{-16v}{(4+v^2)^2}dv$