Let the boxes be Box 1, Box 2, Box 3.
consider the 3 white balls. They can be all of them in one box:
(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)
We can have 2 in one box, and 1 in one of the remaining boxes:
(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)
and there is only one way: (1, 1, 1) to place one white ball in each box
In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.
Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.
Answer: 100
Answer:
Driving to Chicago Driving Back
d=rt
400/8=r(8)/8
r=50 mph < r= 52 mph
Step-by-step explanation:
Answer:
$15 and 50 cents
Step-by-step explanation:
3.25x2=6.50+9=15.50
The answer is B, or y - 6 = 3/4 (x - 4). To put (-4, 6); m = 3/4 in point-slope form, you first start with the point-slope form equation which is y - k = m (x - h). The ordered pair that it wants you to put in is (-4, 6). To figure out where the ordered pair goes, you replace the variables (h, k) with (-4, 6). The h will always be the point on the
x-axis and the k will always will be the point on the y-axis. Putting these together, you now get y - 6 = m (x - 4). As the same in slope-intercept form, or y=mx+b form, the slope in this equation is m. In this equation, m = 3/4. So, the equation in point-slope form is y - 6 = 3/4 (x - 4).
70.36 I believe. :D Hope I helped.