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3 years ago

6. HELP W THIS ONE TOO PLS!!

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

This occurs for the input(s) x where the outputs, f(x) and g(x), are equal. So here, f(x) = g(x) when x = 1, because 5 = 5.

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Which equation represents the parabola shown on the

EastWind [94]

Answer:

y2=-8x is what's graphed so B.

Step-by-step explanation:

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3 years ago

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The lateral area of a right cylinder which has a base diameter of 12 cm and a height of 8 cm is?

garik1379 [7]

Answer:

$A = 301.59\ cm^2$ or $A=96\pi\ cm^2$

Step-by-step explanation:

The lateral area of a cylinder is calculated by the following formula

$A = 2\pi r * h.$

Where r is the radius of the right cylinder and h is the height

In this case we know that the diameter d of the cylinder is

$d=2r\\\\r=\frac{d}{2}\\\\r=\frac{12}{2}\\\\r=6\ cm$

$h=8\ cm$

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$A = 2\pi*6 * 8.$

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$A = 301.59\ cm^2$

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3 years ago

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A polynomial P(x) and a divisor d(x) are given. Use long division to find a quotient Q(x) and the remainder R(x). Express P(x) i

Vilka [71]

It's a bit hard to explain but I hope this helps

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3 years ago

the measure of angle is 7π/6. the measure of its reference angle is *blank* degrees, and sin is *blank*.

marin [14]

The measure of angle θ = 7pi/6. To convert this to degrees, substitute pi with 180 degrees. Pi is always equal to 180 degrees.
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Find the equation for the plane that contains the line x=−1+3t , y=1+2t, z=2+4t and is perpendicular to the plane containing the

Ivan

Let $L$ be the line given by the vector equation

$(-1,1,2) + \lambda(3,2,4) \ , \lambda \in \mathbb{R}$ .

First, we use the director vectors of the lines L1 and L2 to get the

vector equation of the plane containing them, which we denote by $\Pi_1$ . This is,

$\\\\\Pi_1 : (1,-1,5) + \alpha (2,-1,6) + \beta (1,1,-3) \ , \alpha, \beta \in \mathbb{R}\\\\\\$

We observe that $\vec{N} = (2,-1,6)\times(1,1,-3) = (-3,12,3) \ne (0,0,0)$ . Therefore, the vector equation of $\Pi_1$ defines a plane and $\vec{N}$ is a normal vector to $\Pi_1.$

Finally, the vector equation for the wanted plane, which we denote by $\Pi$ , is

$\Pi : (-1,1,2) + r(3,2,4) + s(-3,12,3), r,s \in \mathbb{R} \ .$

Thus, if $s = 0$ , then $L \subset \Pi$ and since $\vec{N}$ is parallel to $\Pi$ , then it is perpendicular to $\Pi_1$ .

8 0

3 years ago