Answer:
1 + and a half = 1 in a half
Step-by-step explanation:
The numerator in the first fraction is closest to
10, so the fraction is nearest to 1.
The numerator in the second fraction is closest to 3, so the fraction is nearest to one-half.
The value of the expression can be estimated as 1 + one-half = 1 and one-half.
First, expand to make it easier
y=x(x^2+5)(x^2+5)
y=x(x^4+10x^2+25)
y=x^5+10x^3+25x
differentiation
y'=5x^4+30x^2+25 is the derivitive
He earns $0.15 every minute. There are 60 minutes every hour and you are trying to found out how much money he is making in 1 minute, so you divide 9 by 60, which will give you the decimal number 0.15. The $29.25 was just a little extra information to try to brush you off.
You have to combine like terms (terms that have the same variable(x,y....) and power/exponent)²³
(4x³ - 4 + 7x) - (2x³ - x - 8) Distribute -1 into (2x³ - x - 8)
(4x³ - 4 + 7x) + (-)2x³ - (-)x - (-)8 (two negative signs cancel each other out and become positive)
(4x³ - 4 + 7x) - 2x³ + x + 8 Now combine like terms
4x³ - 2x³ + 7x + x - 4 + 8 (I rearranged for the like terms to be next to each other)
2x³ + 8x + 4 It is equivalent to B
Combine like terms
(I rearranged for the like terms to be next to each other)
It is equivalent to D
(x² - 2x)(2x + 3) Distribute x² into (2x + 3) and distribute -2x into (2x + 3)
(x²)2x + (x²)3 + (-2x)2x + (-2x)3
When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together
2x³ + 3x² - 4x² - 6x Combine like terms
2x³ - x² - 6x It is equivalent to A
[Info]
When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (You can combine the exponents only if they have the same variable)
For example:
(You can't combine them because they have different exponents of y and x)
Answer:
The taxi driver's average profit per trip is 4.4.
Step-by-step explanation:
Probability of fares picked up in zone A with destinations in zone A = 0.6
Probability of fares picked up in zone A with destinations in zone B = 0.4
Probability of fares picked up in zone B with destinations in zone A = 0.3
Probability of fares picked up in zone B with destinations in zone B = 0.7
The driver's expected profit for a trip entirely in zone A = 6
The driver's expected profit for a trip entirely in zone B = 8
The driver's expected profit for a trip involving both zones is 12
The taxi driver's average profit per trip:
zone A with destinations in zone A = 0.6 * 6 = 3.6
zone A with destinations in zone B = 0.4 * 12 = 4.8
zone B with destinations in zone A = 0.3 * 12 = 3.6
zone B with destinations in zone B = 0.7 * 8 = 5.6
Total profit expected for 4 trips = 17.6
Average profit per trip = 4.4 (17.6/4)
